x^2+(m+1)x+4=0

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Solution for x^2+(m+1)x+4=0 equation:


Simplifying
x2 + (m + 1) * x + 4 = 0

Reorder the terms:
x2 + (1 + m) * x + 4 = 0

Reorder the terms for easier multiplication:
x2 + x(1 + m) + 4 = 0
x2 + (1 * x + m * x) + 4 = 0

Reorder the terms:
x2 + (mx + 1x) + 4 = 0
x2 + (mx + 1x) + 4 = 0

Reorder the terms:
4 + mx + 1x + x2 = 0

Solving
4 + mx + 1x + x2 = 0

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + mx + 1x + -4 + x2 = 0 + -4

Reorder the terms:
4 + -4 + mx + 1x + x2 = 0 + -4

Combine like terms: 4 + -4 = 0
0 + mx + 1x + x2 = 0 + -4
mx + 1x + x2 = 0 + -4

Combine like terms: 0 + -4 = -4
mx + 1x + x2 = -4

Add '-1x' to each side of the equation.
mx + 1x + -1x + x2 = -4 + -1x

Combine like terms: 1x + -1x = 0
mx + 0 + x2 = -4 + -1x
mx + x2 = -4 + -1x

Add '-1x2' to each side of the equation.
mx + x2 + -1x2 = -4 + -1x + -1x2

Combine like terms: x2 + -1x2 = 0
mx + 0 = -4 + -1x + -1x2
mx = -4 + -1x + -1x2

Divide each side by 'x'.
m = -4x-1 + -1 + -1x

Simplifying
m = -4x-1 + -1 + -1x

Reorder the terms:
m = -1 + -4x-1 + -1x

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